GATE XL 2025 Question Paper with Answer Key

GATE XL 2025 question paper with answer key: all 122 questions

All 122 questions from the GATE 2025 Life Sciences (XL) paper, typed out in full, with the official final answer key and every diagram: General Aptitude, Chemistry and all five optional sections.

122questions across all sections
65you answer: GA, XL-P and two sections
100marks, 3 hours
15diagrams, as set in the exam

GATE 2025 Life Sciences (XL) was organised by IIT Roorkee. Every candidate answered General Aptitude (GA) and XL-P Chemistry, then chose two of the five optional sections: XL-Q Biochemistry, XL-R Botany, XL-S Microbiology, XL-T Zoology and XL-U Food Technology. This page has all of them, in the order they were set, so you can practise the two you plan to choose and look at the rest. Each question is tagged with its topic. Tap Show answer under any question to check the official answer.

How to use this pageTry each question before you open its answer. Answers come from the organising institute’s final answer key. For MSQ questions every correct option must be chosen; numerical answers are accepted anywhere in the official range.
Take it as a timed examThe same paper is available as a free, timed test with GATE marking and an instant score: GATE XL 2025 in live exam mode (log in to save your score).
Want full-length practice?The GATE-XL Life Sciences Full Test Series gives you full-length mocks on the GATE pattern, with MCQ, MSQ and numerical questions and GATE marking. See the GATE-XL Life Sciences Full Test Series.

Marking scheme

SectionQuestionsMarksYou answer
GA: General Aptitude10 (5 × 1 mark, 5 × 2 marks)15Compulsory
XL-P: Chemistry17 (9 × 1 mark, 8 × 2 marks)25Compulsory
XL-Q to XL-U: five optional sections19 each (8 × 1 mark, 11 × 2 marks)30 eachAny two
Total you answer651003 hours
Negative markingOnly MCQs are penalised: a wrong 1-mark MCQ loses 1/3 mark and a wrong 2-mark MCQ loses 2/3 mark. MSQ and numerical answer questions have no negative marking, and there is no partial credit on MSQ.

Which topics this paper tested

We tagged every question with its GATE XL syllabus topic. The table shows the three biggest topics in each section; each section below opens with a chart of all its topics.

SectionQuestionsMost-tested topics (questions)
GA General Aptitude10Quantitative Aptitude (4), Verbal Aptitude (3), Analytical Aptitude (3)
XL-P Chemistry17Organic Chemistry (3), Structure & Bonding (3), Thermodynamics (2)
XL-Q Biochemistry19Biomolecules (6), Biochemical Techniques (3), Immunology (3)
XL-R Botany19Plant Physiology & Biochemistry (5), Morphogenesis & Development (3), Genetics & Genomics (3)
XL-S Microbiology19Microbial Growth (4), Microbial Taxonomy & Diversity (4), Microbial Genetics (3)
XL-T Zoology19Biochemistry & Molecular Biology (5), Genetics (3), Developmental Biology (2)
XL-U Food Technology19Food Chemistry & Nutrition (6), Food Products Technology (6), Food Engineering (4)

Jump to a section

GA: General Aptitude (Q1–10)

10 questions (5 of 1 mark, 5 of 2 marks). Compulsory for every XL candidate.

GATE XL 2025, GA General Aptitude: questions by topic
10 questions, tagged by Lesson Basket.
Quantitative Aptitude40%
Verbal Aptitude30%
Analytical Aptitude30%
Topic tags: Lesson Basket. See also our GATE-XL weightage analysis.
Q1Verbal AptitudeGA Q.1 · MCQ · 1 mark, −1/3 for a wrong answer

Even though I had planned to go skiing with my friends, I had to __________ at the last moment because of an injury. Select the most appropriate option to complete the above sentence.

  1. Aback up
  2. Bback of
  3. Cback on
  4. Dback out
Show answer
Answer: (D) back out
Q2Verbal AptitudeGA Q.2 · MCQ · 1 mark, −1/3 for a wrong answer

The President, along with the Council of Ministers, ___________ to visit India next week. Select the most appropriate option to complete the above sentence.

  1. Awish
  2. Bwishes
  3. Cwill wish
  4. Dis wishing
Show answer
Answer: (B) wishes
Q3Quantitative AptitudeGA Q.3 · MCQ · 1 mark, −1/3 for a wrong answer

An electricity utility company charges ₹ 7 per kWh (kilo watt-hour). If a 40-watt desk light is left on for 10 hours each night for 180 days, what would be the cost of energy consumption? If the desk light is on for 2 more hours each night for the 180 days, what would be the percentage-increase in the cost of energy consumption?

  1. A₹ 604.8; 10%
  2. B₹ 504; 20%
  3. C₹ 604.8; 12%
  4. D₹ 720; 15%
Show answer
Answer: (B) ₹ 504; 20%
Q4Analytical AptitudeGA Q.4 · MCQ · 1 mark, −1/3 for a wrong answer

In the context of the given figure, which one of the following options correctly represents the entries in the blocks labelled (i), (ii), (iii), and (iv), respectively?

GATE XL 2025 Q4 figure: In the context of the given figure, which one of the following options correctly represents the entries in the
  1. AQ, M, 12, and 8
  2. BK, L, 10 and 14
  3. CI, J, 10, and 8
  4. DL, K, 12 and 8
Show answer
Answer: (C) I, J, 10, and 8
Q5Quantitative AptitudeGA Q.5 · MCQ · 1 mark, −1/3 for a wrong answer

A bag contains Violet (V), Yellow (Y), Red (R), and Green (G) balls. On counting them, the following results are obtained:

(i) The sum of Yellow balls and twice the number of Violet balls is 50.
(ii) The sum of Violet and Green balls is 50.
(iii) The sum of Yellow and Red balls is 50.
(iv) The sum of Violet and twice the number of Red balls is 50.

Which one of the following Pie charts correctly represents the balls in the bag?

  1. AGATE XL 2025 Q5, option A
  2. BGATE XL 2025 Q5, option B
  3. CGATE XL 2025 Q5, option C
  4. DGATE XL 2025 Q5, option D
Show answer
Answer: (A)
Q6Verbal AptitudeGA Q.6 · MCQ · 2 marks, −2/3 for a wrong answer

“His life was divided between the books, his friends, and long walks. A solitary man, he worked at all hours without much method, and probably courted his fatal illness in this way. To his own name there is not much to show; but such was his liberality that he was continually helping others, and fruits of his erudition are widely scattered, and have gone to increase many a comparative stranger’s reputation.” (From E.V. Lucas’s “A Funeral”) Based only on the information provided in the above passage, which one of the following statements is true?

  1. AThe solitary man described in the passage is dead.
  2. BStrangers helped create a grand reputation for the solitary man described in the passage.
  3. CThe solitary man described in the passage found joy in scattering fruits.
  4. DThe solitary man worked in a court where he fell ill.
Show answer
Answer: (A) The solitary man described in the passage is dead.
Q7Analytical AptitudeGA Q.7 · MCQ · 2 marks, −2/3 for a wrong answer

For the clock shown in the figure, if

O* = O Q S Z P R T, and
X* = X Z P W Y O Q,

then which one among the given options is most appropriate for P*?

GATE XL 2025 Q7 figure: For the clock shown in the figure, if
  1. AP U W R T V X
  2. BP R T O Q S U
  3. CP T V Q S U W
  4. DP S U P R T V
Show answer
Answer: (B) P R T O Q S U
Q8Analytical AptitudeGA Q.8 · MCQ · 2 marks, −2/3 for a wrong answer

Consider a five-digit number PQRST that has distinct digits P, Q, R, S, and T, and satisfies the following conditions:

P < Q
S > P > T
R < T

If integers 1 through 5 are used to construct such a number, the value of P is:

  1. A1
  2. B2
  3. C3
  4. D4
Show answer
Answer: (C) 3
Q9Quantitative AptitudeGA Q.9 · MCQ · 2 marks, −2/3 for a wrong answer

A business person buys potatoes of two different varieties P and Q, mixes them in a certain ratio and sells them at ₹ 192 per kg.

The cost of the variety P is ₹ 800 for 5 kg.
The cost of the variety Q is ₹ 800 for 4 kg.

If the person gets 8% profit, what is the P:Q ratio (by weight)?

  1. A5:4
  2. B3:4
  3. C3:2
  4. D1:1
Show answer
Answer: (A) 5:4
Q10Quantitative AptitudeGA Q.10 · MCQ · 2 marks, −2/3 for a wrong answer

Three villages P, Q, and R are located in such a way that the distance PQ = 13 km, QR = 14 km, and RP = 15 km, as shown in the figure. A straight road joins Q and R. It is proposed to connect P to this road QR by constructing another road. What is the minimum possible length (in km) of this connecting road?

Note: The figure shown is representative.

GATE XL 2025 Q10 figure: Three villages P, Q, and R are located in such a way that the distance PQ = 13 km, QR = 14 km, and RP = 15 km,
  1. A10.5
  2. B11.0
  3. C12.0
  4. D12.5
Show answer
Answer: (C) 12.0

XL-P: Chemistry (Q11–27)

17 questions (9 of 1 mark, 8 of 2 marks). Compulsory for every XL candidate.

GATE XL 2025, XL-P Chemistry: questions by topic
17 questions, tagged by Lesson Basket.
Organic Chemistry17.6%
Structure & Bonding17.6%
Thermodynamics11.8%
Reaction Kinetics11.8%
s, p & d Block Elements11.8%
Biomolecule Chemistry11.8%
Atomic Structure & Periodicity5.9%
Chemical Equilibria5.9%
Electrochemistry5.9%
Topic tags: Lesson Basket. See also our GATE-XL weightage analysis.
Q11Organic ChemistryXL-P Q.1 · MCQ · 1 mark, −1/3 for a wrong answer

The rate of solvolysis for the following tertiary halides in 80% aqueous ethanol at 25 °C follows the order

GATE XL 2025 Q11 figure: The rate of solvolysis for the following tertiary halides in 80% aqueous ethanol at 25 °C follows the order
  1. AI < II < III
  2. BII < III < I
  3. CIII < II < I
  4. DII < I < III
Show answer
Answer: (B) II < III < I
Q12Structure & BondingXL-P Q.2 · MCQ · 1 mark, −1/3 for a wrong answer

The CORRECT order of boiling points for the hydrogen halides is

  1. AHF > HI > HBr > HCl
  2. BHF > HCl > HBr > HI
  3. CHI > HBr > HCl > HF
  4. DHI > HF > HBr > HCl
Show answer
Answer: (A) HF > HI > HBr > HCl
Q13Structure & BondingXL-P Q.3 · MCQ · 1 mark, −1/3 for a wrong answer

The bond order in N22− species is

  1. A2
  2. B2.5
  3. C3
  4. D3.5
Show answer
Answer: (A) 2
Q14ThermodynamicsXL-P Q.4 · MCQ · 1 mark, −1/3 for a wrong answer

The standard enthalpy of the reaction,

C (graphite) + H2O (g) → CO (g) + H2 (g) is found to be +131.3 kJ mol−1 and the ΔfH0 value for CO (g) is –110.5 kJ mol−1.

The value of ΔfH0 (in kJ mol−1) for H2O (g) is

(The standard enthalpies of formation of elements in their reference states are zero at all temperatures)

  1. A+241.8
  2. B0.0
  3. C−241.8
  4. D+20.8
Show answer
Answer: (C) −241.8
Q15Reaction KineticsXL-P Q.5 · MCQ · 1 mark, −1/3 for a wrong answer

The temperature dependence of reaction rates is generally given by the Arrhenius equation. A plot of ln kr against 1/T is a straight line from which the pre-exponential factor ‘A’ and the activation energy ‘Ea’ can be determined.

The CORRECT option regarding this plot is

  1. ASlope: −Ea/R; Intercept on the y-axis: ln A
  2. BSlope: +Ea/2.303R; Intercept on the y-axis: A
  3. CSlope: +Ea/R; Intercept on the y-axis: A
  4. DSlope: −Ea/2.303R; Intercept on the y-axis: ln A
Show answer
Answer: (A) Slope: −Ea/R; Intercept on the y-axis: ln A
Q16ThermodynamicsXL-P Q.6 · MCQ · 1 mark, −1/3 for a wrong answer

The isothermal expansion of one mole of an ideal gas from Vi to Vf at temperature, T occurs in two ways.

Path I: a reversible isothermal expansion;
Path II: free expansion against zero external pressure

The CORRECT option for the values of ΔU, q and w for Path I and Path II is

  1. APath I: ΔU = 0, q > 0, w < 0; Path II: ΔU = 0, q = 0, w = 0
  2. BPath I: ΔU = 0, q > 0, w < 0; Path II: ΔU > 0, q > 0, w = 0
  3. CPath I: ΔU = 0, q < 0, w > 0; Path II: ΔU = 0, q > 0, w < 0
  4. DPath I: ΔU = 0, q < 0, w > 0; Path II: ΔU < 0, q = 0, w = 0
Show answer
Answer: (A) Path I: ΔU = 0, q > 0, w < 0; Path II: ΔU = 0, q = 0, w = 0
Q17Organic ChemistryXL-P Q.7 · MSQ (one or more correct) · 1 mark, no negative marking

The CORRECT statement(s) regarding the given molecules is(are)

GATE XL 2025 Q17 figure: The CORRECT statement(s) regarding the given molecules is(are)
  1. ABoth I and II are achiral molecules.
  2. BBoth II and III are chiral molecules.
  3. CIV is a chiral molecule.
  4. DBoth III and IV are chiral molecules.
Show answer
Answer (select all of these): (A) Both I and II are achiral molecules. and (C) IV is a chiral molecule.
Q18s, p & d Block ElementsXL-P Q.8 · MSQ (one or more correct) · 1 mark, no negative marking

The CORRECT statement(s) about [Ni(CN)4]2−, [Ni(CO)4] and [NiCl4]2− is(are)

(Given: Atomic number of Ni: 28)

  1. ABoth [Ni(CN)4]2− and [Ni(CO)4] are square planar complexes.
  2. B[Ni(CN)4]2− is diamagnetic and [NiCl4]2− is paramagnetic.
  3. CBoth [Ni(CO)4] and [NiCl4]2− are paramagnetic.
  4. D[Ni(CN)4]2− is square planar and [NiCl4]2− is tetrahedral in shape.
Show answer
Answer (select all of these): (B) [Ni(CN)4]2− is diamagnetic and [NiCl4]2− is paramagnetic. and (D) [Ni(CN)4]2− is square planar and [NiCl4]2− is tetrahedral in shape.
Q19Biomolecule ChemistryXL-P Q.9 · Numerical answer · 1 mark, no negative marking

Consider the two pKa values of valine as 2.32 and 9.62. The isoelectric point (pI) of this amino acid is ______. (rounded off to two decimal places)

Type a number as your answer.

Show answer
Answer: any value from 5.96 to 5.98 (numerical answer, as in the official key).
Q20Structure & BondingXL-P Q.10 · MCQ · 2 marks, −2/3 for a wrong answer

A few species are given in Column I. Column II contains the hybrid orbitals used by the central atom of the species for bonding.

The CORRECT match for the species to their central atom hybridization is

(Given: Atomic numbers of B: 5; C: 6; O: 8; F: 9; P: 15; Cl: 17; I: 53)

Column I
Species
Column II
Hybrid orbitals used by the central atom for bonding
i. I3−a. sp
ii. PCl3b. sp2
iii. BF3c. sp3
iv. CO2d. sp3d
  1. Ai−d, ii−c, iii−b, iv−a
  2. Bi−a, ii−d, iii−b, iv−c
  3. Ci−d, ii−c, iii−a, iv−b
  4. Di−d, ii−b, iii−c, iv−a
Show answer
Answer: (A) i−d, ii−c, iii−b, iv−a
Q21Reaction KineticsXL-P Q.11 · MCQ · 2 marks, −2/3 for a wrong answer

For product formation from only one type of reactant (e.g. A → product), the CORRECT match for the order of the reaction (given in Column I) with the half-life expression (given in Column II) is

([A]0 is the initial concentration and kr is the rate constant)

Column I
Order
Column II
Half-life expression
i. ZeroP. ln 2 / kr
ii. FirstQ. [A]0 / 2kr
iii. SecondR. 1 / kr[A]0
S. 2kr / [A]0
  1. Ai−R, ii−P, iii−S
  2. Bi−Q, ii−P, iii−R
  3. Ci−S, ii−R, iii−Q
  4. Di−Q, ii−P, iii−S
Show answer
Answer: (B) i−Q, ii−P, iii−R
Q22Organic ChemistryXL-P Q.12 · MSQ (one or more correct) · 2 marks, no negative marking

The CORRECT statement(s) for the given reactions is(are)

GATE XL 2025 Q22 figure: The CORRECT statement(s) for the given reactions is(are)
  1. AP is formed as the major product in reaction I.
  2. BP is formed as the major product in reaction II.
  3. CQ is formed as the major product in reaction IV.
  4. DR is formed as the major product in reaction III.
Show answer
Answer (select all of these): (A) P is formed as the major product in reaction I. and (B) P is formed as the major product in reaction II. and (C) Q is formed as the major product in reaction IV.
Q23s, p & d Block ElementsXL-P Q.13 · MSQ (one or more correct) · 2 marks, no negative marking

Addition of a few drops of concentrated HCl to an aqueous solution of CoCl2 forms a dark blue complex X. The CORRECT statement(s) for this reaction is(are) (Given: Atomic number of Co: 27)

  1. AX is a centrosymmetric complex.
  2. BThe oxidation state of cobalt does not change in this reaction.
  3. CThe number of unpaired electrons on cobalt in X and in CoCl2 (aqueous solution) are the same.
  4. DThe spin only magnetic moment value for X is 3.87 BM.
Show answer
Answer (select all of these): (B) The oxidation state of cobalt does not change in this reaction. and (C) The number of unpaired electrons on cobalt in X and in CoCl2 (aqueous solution) are the same. and (D) The spin only magnetic moment value for X is 3.87 BM.
Q24Biomolecule ChemistryXL-P Q.14 · MSQ (one or more correct) · 2 marks, no negative marking

The CORRECT statement(s) regarding biomolecules is(are)

  1. AThe N-terminal amino acid of a polypeptide can be identified by Edman’s reagent (phenyl isothiocyanate).
  2. BL-Threonine has only one chiral center.
  3. CCytosine is present both in RNA and DNA.
  4. DA mixture of different amino acids can be separated by ion-exchange chromatography.
Show answer
Answer (select all of these): (A) The N-terminal amino acid of a polypeptide can be identified by Edman’s reagent (phenyl isothiocyanate). and (C) Cytosine is present both in RNA and DNA. and (D) A mixture of different amino acids can be separated by ion-exchange chromatography.
Q25Atomic Structure & PeriodicityXL-P Q.15 · Numerical answer · 2 marks, no negative marking

Energy of the transition from nh = 4 to nl = 2 for hydrogen atom is E × 103 cm−1.

Given: Rydberg constant for hydrogen: 1.097 × 107 m−1.

Value of E is ______________. (rounded off to two decimal places)

Type a number as your answer.

Show answer
Answer: any value from 20.55 to 20.59 (numerical answer, as in the official key).
Q26Chemical EquilibriaXL-P Q.16 · Numerical answer · 2 marks, no negative marking

A non-volatile solute has a molecular weight of 180 g mol−1. Assume that the solute does not associate or dissociate in water, and the boiling-point constant (ebullioscopic constant) of water is 0.51 K kg mol−1.

The amount (in g) of solute added to 500 g of water to elevate the boiling point by 0.153 K is ______. (answer in integer)

Type a number as your answer.

Show answer
Answer: 27 (numerical answer, as in the official key).
Q27ElectrochemistryXL-P Q.17 · Numerical answer · 2 marks, no negative marking

The standard potentials (E0) for the Fe3+/Fe and Fe3+/Fe2+ couples are −0.04 V and +0.76 V, respectively.

Given: Faraday constant = 96500 C mol−1.

The value for E0(Fe2+/Fe), in V, is ____________. (rounded off to two decimal places)

Type a number as your answer.

Show answer
Answer: any value from -0.46 to -0.42 (numerical answer, as in the official key).
Two sections to go. Now test yourself under time
The GATE-XL Life Sciences Test Series gives you full-length mocks on the GATE pattern, with MCQ, MSQ and numerical questions.

XL-Q: Biochemistry (Q28–46)

19 questions (8 of 1 mark, 11 of 2 marks). Optional: answer it only if you pick Biochemistry. From GATE 2027 this section is called XL1.

GATE XL 2025, XL-Q Biochemistry: questions by topic
19 questions, tagged by Lesson Basket.
Biomolecules31.6%
Biochemical Techniques15.8%
Immunology15.8%
Metabolism & Bioenergetics10.5%
Molecular Biology10.5%
Cell Biology10.5%
Enzymes5.3%
Topic tags: Lesson Basket. See also our GATE-XL weightage analysis.
Q28BiomoleculesXL-Q Q.1 · MCQ · 1 mark, −1/3 for a wrong answer

Zinc is essential for the function of

  1. Acarboxypeptidase A.
  2. Bchlorophyll a.
  3. Cmyoglobin.
  4. Dvitamin B12.
Show answer
Answer: (A) carboxypeptidase A.
Q29Metabolism & BioenergeticsXL-Q Q.2 · MCQ · 1 mark, −1/3 for a wrong answer

Which one of the following molecules captures CO2 in the C4 cycle?

  1. A1,3-Bisphosphoglycerate
  2. BOxaloacetate
  3. CPhosphoenolpyruvate
  4. DRibulose-1,5-bisphosphate
Show answer
Answer: (C) Phosphoenolpyruvate
Q30Biochemical TechniquesXL-Q Q.3 · MCQ · 1 mark, −1/3 for a wrong answer

Which one of the following methods separates biomolecules based on their hydrodynamic volumes?

  1. AAnion-exchange chromatography
  2. BCation-exchange chromatography
  3. CSize-exclusion chromatography
  4. DThin-layer chromatography
Show answer
Answer: (C) Size-exclusion chromatography
Q31Biochemical TechniquesXL-Q Q.4 · MCQ · 1 mark, −1/3 for a wrong answer

Which one of the following restriction endonucleases is a blunt cutter?

  1. ABamHI
  2. BEcoRI
  3. CHindIII
  4. DEcoRV
Show answer
Answer: (D) EcoRV
Q32Molecular BiologyXL-Q Q.5 · MCQ · 1 mark, −1/3 for a wrong answer

Which one of the following DNA repair systems requires DNA glycosylases?

  1. ABase-excision
  2. BDirect
  3. CMismatch
  4. DNucleotide-excision
Show answer
Answer: (A) Base-excision
Q33Cell BiologyXL-Q Q.6 · MCQ · 1 mark, −1/3 for a wrong answer

Which one of the following ion channels opens to repolarize the neuronal membrane when an action potential is generated?

  1. ACa2+ channel
  2. BH+ channel
  3. CNa+ channel
  4. DK+ channel
Show answer
Answer: (D) K+ channel
Q34ImmunologyXL-Q Q.7 · MCQ · 1 mark, −1/3 for a wrong answer

Which one of the following is the most sensitive immunoassay?

  1. AImmunoelectrophoresis
  2. BImmunofluorescence
  3. CRadial immunodiffusion
  4. DRadioimmunoassay
Show answer
Answer: (D) Radioimmunoassay
Q35ImmunologyXL-Q Q.8 · MSQ (one or more correct) · 1 mark, no negative marking

Which of the following statements about antibodies is/are correct?

  1. ADifferent antibody classes have different effector functions.
  2. BEach antibody chain consists of an amino-terminal constant region and a carboxy- terminal variable region.
  3. CVariable domains harbour complementarity-determining regions.
  4. DAll antibodies have same half-life.
Show answer
Answer (select all of these): (A) Different antibody classes have different effector functions. and (C) Variable domains harbour complementarity-determining regions.
Q36BiomoleculesXL-Q Q.9 · MCQ · 2 marks, −2/3 for a wrong answer

Which one of the following molecules does NOT contain phosphoanhydride bond(s)?

  1. AAdenosine diphosphate
  2. BAdenosine triphosphate
  3. CFructose-1,6-bisphosphate
  4. DPyrophosphate
Show answer
Answer: (C) Fructose-1,6-bisphosphate
Q37EnzymesXL-Q Q.10 · MCQ · 2 marks, −2/3 for a wrong answer

For an enzyme that follows Michaelis-Menten kinetics, a competitive inhibitor

  1. Aincreases both Km and Vmax.
  2. Bdecreases both Km and Vmax.
  3. Cincreases Km but does not affect Vmax.
  4. Ddecreases Km but does not affect Vmax.
Show answer
Answer: (C) increases Km but does not affect Vmax.
Q38Biochemical TechniquesXL-Q Q.11 · MCQ · 2 marks, −2/3 for a wrong answer

Fӧrster Resonance Energy Transfer does NOT depend on the

  1. Arelative orientation of donor and acceptor.
  2. Bfluorescence quantum yield of acceptor.
  3. Cdistance between donor and acceptor.
  4. Doverlap between donor’s emission and acceptor’s absorption spectra.
Show answer
Answer: (B) fluorescence quantum yield of acceptor.
Q39Cell BiologyXL-Q Q.12 · MCQ · 2 marks, −2/3 for a wrong answer

Phospholipid vesicles prepared in 50 mM KCl were diluted in water. Based on this information, statements P and Q are made. P: The diluted vesicles will develop membrane potential. Q: There is a K+ concentration difference across the vesicular membrane. Which one of the following options is correct?

  1. ABoth P and Q are true.
  2. BP is true but Q is false.
  3. CP is false but Q is true.
  4. DBoth P and Q are false.
Show answer
Answer: (C) P is false but Q is true.
Q40ImmunologyXL-Q Q.13 · MCQ · 2 marks, −2/3 for a wrong answer

Peptide-binding cleft in MHC-I is formed by

  1. Aα1 and α2 domains.
  2. Bα1 and α3 domains.
  3. Cα1 domain and 𝛽2-microglobulin.
  4. Dα2 domain and 𝛽2-microglobulin.
Show answer
Answer: (A) α1 and α2 domains.
Q41BiomoleculesXL-Q Q.14 · MSQ (one or more correct) · 2 marks, no negative marking

Which of the following peptides do/does NOT absorb ultraviolet light above 250 nm wavelength?

  1. AMQRTVWG
  2. BYDEIGVL
  3. CPLASNGK
  4. DGSQTKRL
Show answer
Answer (select all of these): (C) PLASNGK and (D) GSQTKRL
Q42Metabolism & BioenergeticsXL-Q Q.15 · MSQ (one or more correct) · 2 marks, no negative marking

Which of the following is/are peptide hormone(s)?

  1. ACalcitonin
  2. BGlucagon
  3. CSerotonin
  4. DThyroxine
Show answer
Answer (select all of these): (A) Calcitonin and (B) Glucagon
Q43BiomoleculesXL-Q Q.16 · MSQ (one or more correct) · 2 marks, no negative marking

Which of the following is/are heteropolysaccharide(s)?

  1. AChondroitin-4-sulfate
  2. BChitin
  3. CCellulose
  4. DHeparin
Show answer
Answer (select all of these): (A) Chondroitin-4-sulfate and (D) Heparin
Q44BiomoleculesXL-Q Q.17 · Numerical answer · 2 marks, no negative marking

The equilibrium dissociation constant of acetic acid is 1.74 × 10−5 M. The pKa of acetic acid (rounded off to one decimal place) is _____ .

Type a number as your answer.

Show answer
Answer: any value from 4.7 to 4.8 (numerical answer, as in the official key).
Q45BiomoleculesXL-Q Q.18 · Numerical answer · 2 marks, no negative marking

The DNA double helix measures 0.34 nm/bp. The diameter of a nucleosome core particle is 11 nm. If the ratio of wrapped DNA length to nucleosome diameter is 4.51, the length of DNA around the nucleosome (to the nearest integer) is _____ bp.

Type a number as your answer.

Show answer
Answer: 146 (numerical answer, as in the official key).
Q46Molecular BiologyXL-Q Q.19 · Numerical answer · 2 marks, no negative marking

E. coli is grown exclusively in a medium containing 15NH4Cl as the sole nitrogen source. Subsequently, the cells were shifted to a medium containing 14NH4Cl. The molar ratio of hybrid DNA (15N-14N) to light DNA (14N-14N) after four generations (rounded off to two decimal places) will be _____ .

Type a number as your answer.

Show answer
Answer: 0.14 (numerical answer, as in the official key).

XL-R: Botany (Q47–65)

19 questions (8 of 1 mark, 11 of 2 marks). Optional: answer it only if you pick Botany. From GATE 2027 this section is called XL2.

GATE XL 2025, XL-R Botany: questions by topic
19 questions, tagged by Lesson Basket.
Plant Physiology & Biochemistry26.3%
Morphogenesis & Development15.8%
Genetics & Genomics15.8%
Plant Pathology10.5%
Plant Breeding & Genetic Modification10.5%
Plant Systematics5.3%
Plant Anatomy5.3%
Economic Botany5.3%
Ecology & Environment5.3%
Topic tags: Lesson Basket. See also our GATE-XL weightage analysis.
Q47Plant SystematicsXL-R Q.1 · MCQ · 1 mark, −1/3 for a wrong answer

Correctly match the names of the plant taxonomists (Group I) with the titles of the books they authored (Group II).

Group IGroup II
(P) John Hutchinson(1) Classification of Flowering Plants
(Q) Adolf Engler and Karl Prantl(2) Evolution and Classification of Flowering Plants
(R) Arthur Cronquist(3) Die Naturlichen Pflanzenfamilien
(S) Alfred Barton Rendle(4) The Families of Flowering Plants
  1. AP-4; Q-3; R-2; S-1
  2. BP-1; Q-3; R-2; S-4
  3. CP-1; Q-2; R-4; S-3
  4. DP-2; Q-1; R-4; S-3
Show answer
Answer: (A) P-4; Q-3; R-2; S-1
Q48Plant AnatomyXL-R Q.2 · MCQ · 1 mark, −1/3 for a wrong answer

Which one of the following mature cell types is live but usually lacks nucleus?

  1. APhloem parenchyma
  2. BPhloem companion
  3. CPhloem sieve element
  4. DPhloem-pole pericycle
Show answer
Answer: (C) Phloem sieve element
Q49Morphogenesis & DevelopmentXL-R Q.3 · MCQ · 1 mark, −1/3 for a wrong answer

Correctly match the carnivorous plants (Group I) with the organs (Group II) they modify to trap the prey.

Group IGroup II
(P) Pitcher plant (Nepenthes)(1) Leaf
(Q) Bladderwort (Utricularia)(2) Fruit
(R) Sundew (Drosera)(3) Stem
(S) Venus flytrap (Dionaea)(4) Tendril
  1. AP-1; Q-2; R-3; S-1
  2. BP-1; Q-1; R-1; S-1
  3. CP-2; Q-2; R-2; S-2
  4. DP-2; Q-4; R-1; S-1
Show answer
Answer: (B) P-1; Q-1; R-1; S-1
Q50Economic BotanyXL-R Q.4 · MCQ · 1 mark, −1/3 for a wrong answer

Which one of the following commercially important carbohydrates is naturally produced only by the members of the plant kingdom?

  1. ACellulose
  2. BPectin
  3. CChitin
  4. DStarch
Show answer
Answer: (B) Pectin
Q51Plant PathologyXL-R Q.5 · MCQ · 1 mark, −1/3 for a wrong answer

Which one of the following agents causes the necrotic ring spot disease in stone fruits?

  1. AFungi
  2. BBacteria
  3. CVirus
  4. DNematodes
Show answer
Answer: (C) Virus
Q52Plant PathologyXL-R Q.6 · MSQ (one or more correct) · 1 mark, no negative marking

Identify the correct statement(s) with respect to plant disease.

  1. AHairy root disease in tobacco is caused by Agrobacterium tumefaciens
  2. BLoose smut of barley is caused by Ustilago nuda
  3. CStem rust of grape is caused by Plasmopara viticola
  4. DFire blight in pear is caused by Erwinia amylovora
Show answer
Answer (select all of these): (B) Loose smut of barley is caused by Ustilago nuda and (D) Fire blight in pear is caused by Erwinia amylovora
Q53Plant Breeding & Genetic ModificationXL-R Q.7 · MSQ (one or more correct) · 1 mark, no negative marking

Which of the following molecular approaches can be used to generate complete knock-out of a target gene in plants?

  1. AHomologous recombination
  2. BCRISPR-Cas9
  3. CAntisense RNA technique
  4. DActivation tagging
Show answer
Answer (select all of these): (A) Homologous recombination and (B) CRISPR-Cas9
Q54Genetics & GenomicsXL-R Q.8 · Numerical answer · 1 mark, no negative marking

If an egg cell of a diploid plant species has 10 chromosomes, the expected number of chromosomes in a double trisomic somatic cell of this species would be _______________ (Answer in integer).

Type a number as your answer.

Show answer
Answer: 22 (numerical answer, as in the official key).
Q55Plant Physiology & BiochemistryXL-R Q.9 · MCQ · 2 marks, −2/3 for a wrong answer

In the history of photosynthetic research, the empirical reaction of photosynthesis was first proposed for green plants (equation 1), followed by another reaction for purple sulfur bacteria (equation 2), leading to a generalized equation for photosynthesis (equation 3)

CO2 + H2O —(light)→ (CH2O) + O2 (equation 1)
CO2 + 2H2S —(light)→ (CH2O) + H2O + 2S (equation 2)
CO2 + 2H2A —(light)→ (CH2O) + H2O + 2A (equation 3)

where H2A in equation 3 is a generalized electron donor.

Which one of the following statements is DISPROVEN by equation 3?

  1. AThe source of oxygen produced in photosynthesis in green plants is CO2
  2. BThe source of oxygen produced in photosynthesis in green plants is H2O
  3. CLight is essential in every form of photosynthesis
  4. DGlucose is the end product in all forms of photosynthesis
Show answer
Answer: (A) The source of oxygen produced in photosynthesis in green plants is CO2
Q56Morphogenesis & DevelopmentXL-R Q.10 · MCQ · 2 marks, −2/3 for a wrong answer

Consider a diploid plant species where the cells in the epidermis (the outermost single cell layer) always divide in the anticlinal orientation. If one such cell within the central zone of the shoot apical meristem (SAM) spontaneously becomes tetraploid at the seedling stage, which one of the following cellular arrangements would be most likely observed if the meristem is examined at the adult stage?

  1. AOnly one tetraploid cell in the epidermis
  2. BMany tetraploid cells in the epidermis
  3. CAll cells in the entire SAM tetraploid
  4. DAll cells in the entire SAM diploid
Show answer
Answer: (B) Many tetraploid cells in the epidermis
Q57Plant Physiology & BiochemistryXL-R Q.11 · MCQ · 2 marks, −2/3 for a wrong answer

Correctly match the photosynthetic pathways (Group I) with their first stable products (Group II) in respective plants (Group III)

Group IGroup IIGroup III
(P) C3 cycle(1) 3-Phosphoglycerate(a) Wheat
(Q) C4 cycle(2) Glyceraldehyde-3-phosphate(b) Sugarcane
(R) CAM(3) Oxaloacetate(c) Pineapple
  1. AP-1-a; Q-3-b; R-3-c
  2. BP-1-a; Q-2-b; R-3-c
  3. CP-1-b; Q-3-a; R-2-c
  4. DP-1-b; Q-2-c; R-2-a
Show answer
Answer: (A) P-1-a; Q-3-b; R-3-c
Q58Genetics & GenomicsXL-R Q.12 · MCQ · 2 marks, −2/3 for a wrong answer

The following table summarizes the flowering time behavior (days to flower) and the transcript levels in four genotypes of a plant species.

GenotypeDays to flowerTranscript level of gene ATranscript level of gene B
Wild type30NormalNormal
a mutant15NilIncreased
b mutant60NormalNil
ab double mutant60NilNil

Which one of the following genetic pathways best explains the observations shown in the table?

  1. AA gene activates B, which suppresses flowering transition
  2. BA gene suppresses B, which promotes flowering transition
  3. CB gene activates A, which suppresses flowering transition
  4. DB gene suppresses A, which promotes flowering transition
Show answer
Answer: (B) A gene suppresses B, which promotes flowering transition
Q59Plant Physiology & BiochemistryXL-R Q.13 · MCQ · 2 marks, −2/3 for a wrong answer

Correctly match the economically important specialized metabolites (Group I) with their broad chemical classes (Group II).

Group IGroup II
(P) Azadirachtin(1) Monoterpene
(Q) Saponin(2) Alkaloid
(R) Gallocatechin(3) Triterpene glycoside
(S) Cocaine(4) Polyphenol
(T) Menthol(5) Triterpene
  1. AP-5; Q-3; R-2; S-4; T-1
  2. BP-2; Q-4; R-3; S-1; T-5
  3. CP-5; Q-3; R-4; S-2; T-1
  4. DP-3; Q-5; R-4; S-2; T-1
Show answer
Answer: (C) P-5; Q-3; R-4; S-2; T-1
Q60Morphogenesis & DevelopmentXL-R Q.14 · MCQ · 2 marks, −2/3 for a wrong answer

Correctly match the following Arabidopsis genes (Group I) and the biological processes they primarily regulate (Group II).

Group IGroup II
(P) CLAVATA3(1) Organ identity in flower
(Q) CONSTANS(2) Cell-type specification in root meristem
(R) SCARECROW(3) Meristem size in shoot
(S) AGAMOUS(4) Photoperiodic floral transition
  1. AP-3; Q-4; R-1; S-2
  2. BP-1; Q-3; R-2; S-4
  3. CP-3; Q-4; R-2; S-1
  4. DP-4; Q-1; R-3; S-2
Show answer
Answer: (C) P-3; Q-4; R-2; S-1
Q61Plant Breeding & Genetic ModificationXL-R Q.15 · MCQ · 2 marks, −2/3 for a wrong answer

Correctly match the enzymes used as selectable markers (Group I) and the chemicals used for their selection (Group II).

Group IGroup II
(P) Neomycin phosphotransferase(1) Bialaphos
(Q) Phosphinothricin acetyltransferase(2) Kanamycin
(R) Dihydrofolate reductase(3) Glyphosate
(S) 5-Enolpyruvyl shikimate 3-phosphate synthase(4) Methotrexate
  1. AP-2; Q-1; R-4; S-3
  2. BP-1; Q-2; R-3; S-4
  3. CP-2; Q-4; R-1; S-3
  4. DP-3; Q-4; R-1; S-2
Show answer
Answer: (A) P-2; Q-1; R-4; S-3
Q62Plant Physiology & BiochemistryXL-R Q.16 · MSQ (one or more correct) · 2 marks, no negative marking

Which of the following sequential reactions correctly represent(s) the flow of electrons from NADH to O2 in plant mitochondrial electron transport chain?

  1. ANADH dehydrogenase → Ubiquinone → Succinate dehydrogenase → Cytochrome bc1 → Cytochrome c → Cytochrome c oxidase
  2. BNADH dehydrogenase → Succinate dehydrogenase → Ubiquinone → Cytochrome c → Cytochrome bc1 → Cytochrome c oxidase
  3. CNADH dehydrogenase → Ubiquinone → Alternative oxidase
  4. DNADH dehydrogenase → Alternative oxidase → Ubiquinone
Show answer
Answer (select all of these): (A) NADH dehydrogenase → Ubiquinone → Succinate dehydrogenase → Cytochrome bc1 → Cytochrome c → Cytochrome c oxidase and (C) NADH dehydrogenase → Ubiquinone → Alternative oxidase
Q63Ecology & EnvironmentXL-R Q.17 · MSQ (one or more correct) · 2 marks, no negative marking

If rabbits are introduced in an isolated grassland for the first time, which of the following growth curves (shown using dashed line) is/are theoretically possible population dynamics over time?

GATE XL 2025 Q63 figure: If rabbits are introduced in an isolated grassland for the first time, which of the following growth curves (s
  1. AP
  2. BQ
  3. CR
  4. DS
Show answer
Answer (select all of these): (A) P and (B) Q and (D) S
Q64Plant Physiology & BiochemistryXL-R Q.18 · MSQ (one or more correct) · 2 marks, no negative marking

Which of the following reactions in plants is/are catalyzed by the malic enzymes?

  1. AMalate + NAD+ → Pyruvate + CO2 + NADH
  2. BMalate + NAD+ → Oxaloacetate + NADH
  3. CMalate → Fumarate
  4. DMalate + NADP+ → Pyruvate + CO2 + NADPH
Show answer
Answer (select all of these): (A) Malate + NAD+ → Pyruvate + CO2 + NADH and (D) Malate + NADP+ → Pyruvate + CO2 + NADPH
Q65Genetics & GenomicsXL-R Q.19 · Numerical answer · 2 marks, no negative marking

In a genetic cross between a true-breeding tall parent bearing red flowers and a true-breeding dwarf parent bearing white flowers, only tall plants with red flowers are obtained in the F1 population. Considering these two traits segregate independently, if one tall individual is selected from the F2 population, the probability that it would be genotypically homozygous for plant height and make red flowers is __________ (Round off to two decimal places).

Type a number as your answer.

Show answer
Answer: any value from 0.24 to 0.26 (numerical answer, as in the official key).

XL-S: Microbiology (Q66–84)

19 questions (8 of 1 mark, 11 of 2 marks). Optional: answer it only if you pick Microbiology. From GATE 2027 this section is called XL3.

GATE XL 2025, XL-S Microbiology: questions by topic
19 questions, tagged by Lesson Basket.
Microbial Growth21.1%
Microbial Taxonomy & Diversity21.1%
Microbial Genetics15.8%
Microbial Metabolism15.8%
Microbial Pathogenesis & Immunology10.5%
Historical Perspective5.3%
Prokaryotic Cells5.3%
Microbial Ecology & Applied Microbiology5.3%
Topic tags: Lesson Basket. See also our GATE-XL weightage analysis.
Q66Microbial GeneticsXL-S Q.1 · MCQ · 1 mark, −1/3 for a wrong answer

Which one of the following metabolites is associated with bacterial stringent response?

  1. ACyclic di-GMP (CDG)
  2. BGuanosine tetraphosphate (ppGpp)
  3. CCyclic-AMP (cAMP)
  4. DCyclic-GMP (cGMP)
Show answer
Answer: (B) Guanosine tetraphosphate (ppGpp)
Q67Microbial Pathogenesis & ImmunologyXL-S Q.2 · MCQ · 1 mark, −1/3 for a wrong answer

India is aiming to be free of tuberculosis by 2025. One of the key approaches for this program is DOTS. Which one of the following options is the full form of DOTS?

  1. ADirectly observed therapy short-course
  2. BDirectly observed tuberculosis short-course
  3. CDistrict operated therapy system
  4. DDirectly operated therapy short-course
Show answer
Answer: (A) Directly observed therapy short-course
Q68Microbial GrowthXL-S Q.3 · MCQ · 1 mark, −1/3 for a wrong answer

Correctly match the bacterial type in Column I with their corresponding environmental niche in Column II.

Column IColumn II
P. Psychrophilei. Pressure greater than 380 atm
Q. Barophileii. Temperature between 15°C and 45°C
R. Mesophileiii. Temperature below 15°C
S. Halophileiv. pH less than 3.0
v. Salt concentration greater than 2M
  1. AP – iii; Q – i; R – ii; S – v
  2. BP – ii; Q – iii; R – i; S – v
  3. CP – i; Q – iv; R – iii; S – v
  4. DP – v; Q – iii; R – iv; S – i
Show answer
Answer: (A) P – iii; Q – i; R – ii; S – v
Q69Historical PerspectiveXL-S Q.4 · MCQ · 1 mark, −1/3 for a wrong answer

Robert Koch used a meat-infused nutrient medium for which one of the following purposes?

  1. ATo grow disease causing microorganisms.
  2. BTo demonstrate presence of microorganisms in air.
  3. CTo test the efficiency of sterilization approaches.
  4. DTo demonstrate antimicrobial activity of soil isolates.
Show answer
Answer: (A) To grow disease causing microorganisms.
Q70Microbial GrowthXL-S Q.5 · MCQ · 1 mark, −1/3 for a wrong answer

A penicillin sensitive Escherichia coli population is exposed to a lethal dose (200 µg/ml) of penicillin. Assuming density-independent mortality, which one of the following relationships would describe the number of surviving bacteria (N) over time (T)?

  1. AExponential
  2. BLinear
  3. CSigmoidal
  4. DParabolic
Show answer
Answer: (A) Exponential
Q71Microbial MetabolismXL-S Q.6 · MCQ · 1 mark, −1/3 for a wrong answer

A bacterium obtains energy from a chemical source by the oxidation of reduced NO2−, with CO2 as the principal carbon source. Which one of the following nutritional groups does this bacterium belong to?

  1. APhotoautotroph.
  2. BPhotoheterotroph.
  3. CChemoautotroph.
  4. DChemoheterotroph.
Show answer
Answer: (C) Chemoautotroph.
Q72Microbial GeneticsXL-S Q.7 · MCQ · 1 mark, −1/3 for a wrong answer

The origin of the Escherichia coli chromosome on the genetic map is shown below.

GATE XL 2025 Q72 figure: The origin of the Escherichia coli chromosome on the genetic map is shown below.

Bidirectional replication is a feature of this system and both replication forks move at the same rate. Which one of the following sequences of replication of the genes is correct?

  1. AABCDEFG
  2. BAGBFCDE
  3. CGAFBECD
  4. DGAFEBCD
Show answer
Answer: (B) AGBFCDE
Q73Microbial MetabolismXL-S Q.8 · MSQ (one or more correct) · 1 mark, no negative marking

Which of the following sites is/are the location(s) of ATP generation through oxidative phosphorylation in Escherichia coli?

  1. AInner membrane only
  2. BOuter membrane only
  3. CBoth outer membrane and inner membrane
  4. DMesosome
Show answer
Answer (select all of these): (A) Inner membrane only and (D) Mesosome
Q74Microbial Pathogenesis & ImmunologyXL-S Q.9 · MCQ · 2 marks, −2/3 for a wrong answer

The adaptive immune response in an animal involves the generation of antibodies against an invading bacterial pathogen. The following graph represents antibody titer levels in a mammal exposed twice to the pathogen.

GATE XL 2025 Q74 figure: The adaptive immune response in an animal involves the generation of antibodies against an invading bacterial

Which one of the following options correctly pairs antibodies to peak I and peak II in the graph?

  1. APeak I – IgG; Peak II – IgM
  2. BPeak I – IgM; Peak II – IgG
  3. CPeak I – IgE; Peak II – IgG
  4. DPeak I – IgG; Peak II – IgG
Show answer
Answer: (B) Peak I – IgM; Peak II – IgG
Q75Microbial Taxonomy & DiversityXL-S Q.10 · MCQ · 2 marks, −2/3 for a wrong answer

Carl Woese established that short subunit rRNA sequences can be used to reveal evolutionary relationships between various organisms. Based on this, which one of the following options is the established phylogenetic arrangement of the three domains of life?

GATE XL 2025 Q75 figure: Carl Woese established that short subunit rRNA sequences can be used to reveal evolutionary relationships betw
  1. AI
  2. BIV
  3. CII
  4. DIII
Show answer
Answer: (C) II
Q76Microbial Taxonomy & DiversityXL-S Q.11 · MCQ · 2 marks, −2/3 for a wrong answer

Correctly match the viruses listed in Column I with the nature of their corresponding genetic materials listed in Column II.

Column IColumn II
P. Bacteriophage lambdai. dsDNA
Q. Bacteriophage M13ii. ssDNA
R. Coronavirusiii. ssRNA
S. Reovirusiv. dsRNA
  1. AP – i; Q – iv; R – iii; S – ii
  2. BP – iv; Q – ii; R – i; S – iii
  3. CP – i; Q – ii; R – iii; S – iv
  4. DP – i; Q – iii; R – ii; S – iv
Show answer
Answer: (C) P – i; Q – ii; R – iii; S – iv
Q77Microbial GeneticsXL-S Q.12 · MCQ · 2 marks, −2/3 for a wrong answer

A culture of lac+ Escherichia coli is grown in a medium lacking lactose or any other β-galactoside. The response of the lac operon upon induction by lactose can be monitored by measuring the levels of lac mRNA, β-galactosidase enzyme and permease enzyme. Which one of the following profiles correctly captures the on-off response to lactose?

GATE XL 2025 Q77 figure: A culture of lac + Escherichia coli is grown in a medium lacking lactose or any other β-galactoside. The respo
  1. AP
  2. BQ
  3. CR
  4. DS
Show answer
Answer: (A) P
Q78Prokaryotic CellsXL-S Q.13 · MSQ (one or more correct) · 2 marks, no negative marking

Which option(s) correctly match(es) the structures in a bacterial cell (Column I) with their corresponding functions (Column II).

Column IColumn II
P. Cell walli. Protection from osmotic stress
Q. Fimbriaeii. Attachment to surfaces
R. Flagellaiii. Motility
S. Piliiv. Transfer of genetic material
  1. AP – i; Q – ii; R – iii; S – iv
  2. BP – i; Q – iii; R – iii; S – iv
  3. CP – i; Q – iv; R – ii; S – iii
  4. DP – ii; Q – iv; R – i; S – iii
Show answer
Answer (select all of these): (A) P – i; Q – ii; R – iii; S – iv
Q79Microbial Taxonomy & DiversityXL-S Q.14 · MSQ (one or more correct) · 2 marks, no negative marking

Which of the following statements regarding micro-organisms is/are correct?

  1. AThe free-living bacterium Wolbachia is a human parasite.
  2. BMyxococcus are a group of predatory bacteria.
  3. CDictyostelium is a slime mold that aggregates to form social groups.
  4. DActinomycetes in soil are involved in producing earthy odours.
Show answer
Answer (select all of these): (B) Myxococcus are a group of predatory bacteria. and (C) Dictyostelium is a slime mold that aggregates to form social groups. and (D) Actinomycetes in soil are involved in producing earthy odours.
Q80Microbial Ecology & Applied MicrobiologyXL-S Q.15 · MSQ (one or more correct) · 2 marks, no negative marking

Which of the following is/are example(s) of animal-microbe mutualism?

  1. AHuman – Mycobacterium tuberculosis
  2. BDog – Rabies lyssavirus
  3. CHuman – Lactobacillus plantarum
  4. DCow – Ruminococcus albus
Show answer
Answer (select all of these): (C) Human – Lactobacillus plantarum and (D) Cow – Ruminococcus albus
Q81Microbial MetabolismXL-S Q.16 · MSQ (one or more correct) · 2 marks, no negative marking

Which of the following reactions is/are catalyzed by aldolase?

  1. ADihydroxyacetone phosphate + Glyceraldehye-3-phosphate → Fructose 1,6-biphosphate
  2. BDihydroxyacetone phosphate + Erythrose-4-phosphate → Sedoheptulose-1,7-biphosphate
  3. CDihydroxyacetone phosphate → Glyceraldehyde-3-phosphate
  4. DGlyceraldehye-3-phosphate + Erythrose-4-phosphate → Sedoheptulose-1,7-biphosphate
Show answer
Answer (select all of these): (A) Dihydroxyacetone phosphate + Glyceraldehye-3-phosphate → Fructose 1,6-biphosphate and (B) Dihydroxyacetone phosphate + Erythrose-4-phosphate → Sedoheptulose-1,7-biphosphate
Q82Microbial GrowthXL-S Q.17 · MSQ (one or more correct) · 2 marks, no negative marking

Which option(s) correctly match(es) the Antibiotic with their corresponding Target?

AntibioticTarget
P. Penicillini. Ribosome
Q. Kanamycinii. RNA polymerase
R. Rifampiciniii. DNA gyrase
S. Nalidixic acidiv. Transpeptidase
T. Ciprofloxacin
  1. AP – iv; Q – i; R – ii; S – iii
  2. BP – ii; Q – iv; R – i; S – iii
  3. CP – iv; Q – i; R – ii; T – iii
  4. DP – iv; Q – iii; R – ii; T – i
Show answer
Answer (select all of these): (A) P – iv; Q – i; R – ii; S – iii and (C) P – iv; Q – i; R – ii; T – iii
Q83Microbial Taxonomy & DiversityXL-S Q.18 · Numerical answer · 2 marks, no negative marking

The doubling time of Escherichia coli is 30 minutes in a culture medium containing glucose and yeast extract. Phage T7 has a life cycle of 20 minutes and a burst size of 200 phage per infected E. coli cell. Phage absorption is instantaneous and occurs at 1 multiplicity of infection (MOI). Bacteria infected with multiple or single phage give the same burst. 5000 plaque forming units of T7 phage are added to a culture of 2 × 107 E. coli cells.

Assuming normal division, the E. coli culture will lyse completely by _____ full cycles of bacterial division. (Answer in integer)

Type a number as your answer.

Show answer
Answer: 2 (numerical answer, as in the official key).
Q84Microbial GrowthXL-S Q.19 · Numerical answer · 2 marks, no negative marking

A polymerase chain reaction (PCR) based diagnosis test was performed on a bacterial sample targeting a specific gene. There are 3 copies of this gene in the bacterial genome. Prior to DNA extraction, the bacteria were incubated to allow one cycle of growth. 3072 amplicon copies were obtained after 9 cycles of the PCR. Assume 100% efficiency at each step. The initial bacterial count in the sample was _______. (Answer in integer)

Type a number as your answer.

Show answer
Answer: 1 (numerical answer, as in the official key).

XL-T: Zoology (Q85–103)

19 questions (8 of 1 mark, 11 of 2 marks). Optional: answer it only if you pick Zoology. From GATE 2027 this section is called XL4.

GATE XL 2025, XL-T Zoology: questions by topic
19 questions, tagged by Lesson Basket.
Biochemistry & Molecular Biology26.3%
Genetics15.8%
Developmental Biology10.5%
Evolution10.5%
Parasitology & Immunology10.5%
Animal Behaviour5.3%
Animal Diversity5.3%
Cell Biology5.3%
Animal Anatomy & Physiology5.3%
Ecology5.3%
Topic tags: Lesson Basket. See also our GATE-XL weightage analysis.
Q85Animal BehaviourXL-T Q.1 · MCQ · 1 mark, −1/3 for a wrong answer

Which one of the following is a “brood parasite” ?

  1. APigeon
  2. BSparrow
  3. CGoose
  4. DCuckoo
Show answer
Answer: (D) Cuckoo
Q86Developmental BiologyXL-T Q.2 · MCQ · 1 mark, −1/3 for a wrong answer

During the development of a mammalian embryo, “yolk sac” is formed by which one of the following?

  1. ASyncytiotrophoblast
  2. BPrimitive endoderm (hypoblast)
  3. CAmniotic ectoderm
  4. DEmbryonic epiblast
Show answer
Answer: (B) Primitive endoderm (hypoblast)
Q87Animal DiversityXL-T Q.3 · MCQ · 1 mark, −1/3 for a wrong answer

The animals belonging to which one of the following phyla are characterized by “segmented body” ?

  1. AAnnelida
  2. BCnidaria
  3. CEchinodermata
  4. DPorifera
Show answer
Answer: (A) Annelida
Q88EvolutionXL-T Q.4 · MCQ · 1 mark, −1/3 for a wrong answer

Which one of the following is a “post-zygotic” isolating mechanism of speciation?

  1. ABehavioral isolation
  2. BFertilization failure
  3. CHybrid sterility
  4. DSeasonal isolation
Show answer
Answer: (C) Hybrid sterility
Q89Cell BiologyXL-T Q.5 · MCQ · 1 mark, −1/3 for a wrong answer

Desmosomes are

  1. Aintermediate filament-based cell adhesion complexes.
  2. Bprotein synthesizing macromolecular complexes.
  3. Csubcellular organelles.
  4. DDNA-protein complexes.
Show answer
Answer: (A) intermediate filament-based cell adhesion complexes.
Q90Animal Anatomy & PhysiologyXL-T Q.6 · MCQ · 1 mark, −1/3 for a wrong answer

The “foramen of Panizza” is found in which one of the following groups of animals?

  1. AFishes
  2. BCrocodiles
  3. CFrogs
  4. DDolphins
Show answer
Answer: (B) Crocodiles
Q91EvolutionXL-T Q.7 · Numerical answer · 1 mark, no negative marking

Imagine a population of diploid species in Hardy-Weinberg equilibrium. The population has two alleles for a gene which are ‘a’ and ‘A’. The number of individuals with ‘aa’ genotype in this population is 1 in 10000. The frequency of the allele ‘A’ in the population is ______ (up to two decimal places)

Type a number as your answer.

Show answer
Answer: 0.99 (numerical answer, as in the official key).
Q92Biochemistry & Molecular BiologyXL-T Q.8 · Numerical answer · 1 mark, no negative marking

A PCR was setup to amplify a 500 nucleotides-long DNA. The dNTPs in the reaction mixture were radiolabeled. The percentage (%) of radiolabeled single- stranded DNA after three cycles will be ______ (up to one decimal place)

Type a number as your answer.

Show answer
Answer: 87.5 (numerical answer, as in the official key).
Q93Parasitology & ImmunologyXL-T Q.9 · MCQ · 2 marks, −2/3 for a wrong answer

Match the molecules in Column-I with their properties/functions mentioned in Column-II

Column-IColumn-II
P. IgM1. Involved in antigen presentation
Q. IgE2. Predominant antibody type in various body secretions
R. IgA3. Can pass through placenta
S. MHC4. Associated with allergic reaction
5. Contains ten heavy and light chains
  1. AP−3 ; Q−2 ; R−4 ; S−5
  2. BP−5 ; Q−4 ; R−2 ; S−1
  3. CP−2 ; Q−3 ; R−4; S−1
  4. DP−5 ; Q−4 ; R−2 ; S−5
Show answer
Answer: (B) P−5 ; Q−4 ; R−2 ; S−1
Q94Parasitology & ImmunologyXL-T Q.10 · MCQ · 2 marks, −2/3 for a wrong answer

Match the following human diseases in Column-I with their causal organism in Column-II

Column-IColumn-II
P. Sleeping sickness1. Trypanosoma cruzi
Q. Chagas disease2. Trypanosoma brucei
R. Elephantiasis3. Borrelia burgdorferi
S. Lyme disease4. Wuchereria bancrofti
5. Rickettsia rickettsii
  1. AP−3 ; Q−1 ; R−4 ; S−5
  2. BP−1 ; Q−2 ; R−3 ; S−4
  3. CP−2 ; Q−4 ; R−1 ; S−3
  4. DP−2 ; Q−1 ; R−4 ; S−3
Show answer
Answer: (D) P−2 ; Q−1 ; R−4 ; S−3
Q95Biochemistry & Molecular BiologyXL-T Q.11 · MCQ · 2 marks, −2/3 for a wrong answer

Match the molecules in Column-I with their correct property/function in Column-II

Column-IColumn-II
P. RNase P1. rRNA gene transcription
Q. RNA Polymerase-I2. Gene silencing
R. siRNA3. Cas9-mediated genome editing
S. Guide RNA4. Ribozymes
5. tRNA gene transcription
  1. AP−4 ; Q−5 ; R−2 ; S−3
  2. BP−5 ; Q−1 ; R−3 ; S−4
  3. CP−4 ; Q−1 ; R−2 ; S−3
  4. DP−1 ; Q−3 ; R−4 ; S−2
Show answer
Answer: (C) P−4 ; Q−1 ; R−2 ; S−3
Q96GeneticsXL-T Q.12 · MCQ · 2 marks, −2/3 for a wrong answer

What would be the number of genotypes and phenotypes, respectively, from a cross between genotypes AaBBCcDd and AaBBCcDd ? Assume independent assortment and simple dominant-recessive relationship in each gene pair.

  1. A8 and 4
  2. B12 and 4
  3. C27 and 8
  4. D14 and 8
Show answer
Answer: (C) 27 and 8
Q97Biochemistry & Molecular BiologyXL-T Q.13 · MSQ (one or more correct) · 2 marks, no negative marking

Nucleosomes are made up of DNA and histones. Histones undergo various kind of modifications by different groups of proteins. They are known as histone writers, readers and erasers. Which of the following is/are histone writer(s)?

  1. AHistone acetyl transferases
  2. BHistone methyl transferases
  3. CHistone deacetylases
  4. DDNA methyl transferases
Show answer
Answer (select all of these): (A) Histone acetyl transferases and (B) Histone methyl transferases
Q98Biochemistry & Molecular BiologyXL-T Q.14 · MSQ (one or more correct) · 2 marks, no negative marking

The expression of a gene is regulated by a transcription factor. Which of the following techniques can be used to identify the region in its promoter where the transcription factor binds?

  1. AS1 nuclease mapping
  2. BChromatin immunoprecipitation followed by sequencing
  3. CElectrophoretic mobility shift assay
  4. DDNase I footprinting
Show answer
Answer (select all of these): (B) Chromatin immunoprecipitation followed by sequencing and (D) DNase I footprinting
Q99EcologyXL-T Q.15 · MSQ (one or more correct) · 2 marks, no negative marking

Which of the following animals in India are included under “critically endangered” threat category as per the Red Data List of IUCN?

  1. ANamdapha Flying Squirrel
  2. BIndian Rhinoceros
  3. CNicobar Shrew
  4. DClouded Leopard
Show answer
Answer (select all of these): (A) Namdapha Flying Squirrel and (C) Nicobar Shrew
Q100Developmental BiologyXL-T Q.16 · MSQ (one or more correct) · 2 marks, no negative marking

Which of the following statements in relation to cell movement during gastrulation in Sea urchin is/are correct?

  1. ADelamination leads to the formation of endoderm
  2. BIngression leads to the development of mesoderm
  3. CInvolution leads to the development of ectoderm
  4. DInvagination leads to the development of endoderm
Show answer
Answer (select all of these): (B) Ingression leads to the development of mesoderm and (D) Invagination leads to the development of endoderm
Q101GeneticsXL-T Q.17 · MSQ (one or more correct) · 2 marks, no negative marking

Which of the following genetic disorders is/are caused by trinucleotide repeat expansions?

  1. AHuntington’s disease
  2. Bβ-thalassemia
  3. CFragile X syndrome
  4. DCystic fibrosis
Show answer
Answer (select all of these): (A) Huntington’s disease and (C) Fragile X syndrome
Q102GeneticsXL-T Q.18 · Numerical answer · 2 marks, no negative marking

The mother and the father of five children are carriers (heterozygous) of an autosomal recessive allele that causes cystic fibrosis. The probability of having exactly three normal children among five is ______ (up to two decimal places)

Type a number as your answer.

Show answer
Answer: any value from 0.25 to 0.27 (numerical answer, as in the official key).
Q103Biochemistry & Molecular BiologyXL-T Q.19 · Numerical answer · 2 marks, no negative marking

An enzyme, which follows Michaelis-Menten equation, catalyzes the reaction A→B. When enzyme and substrate concentrations are 15 nM and 10 µM, respectively, the reaction velocity is 5 µM s−1. If Km for the substrate A is 5 µM, the kinetic efficiency of the enzyme will be _______ × 106 M−1 s−1 (in integer)

Type a number as your answer.

Show answer
Answer: 100 (numerical answer, as in the official key).

XL-U: Food Technology (Q104–122)

19 questions (8 of 1 mark, 11 of 2 marks). Optional: answer it only if you pick Food Technology. From GATE 2027 this section is called XL5.

GATE XL 2025, XL-U Food Technology: questions by topic
19 questions, tagged by Lesson Basket.
Food Chemistry & Nutrition31.6%
Food Products Technology31.6%
Food Engineering21.1%
Food Microbiology15.8%
Topic tags: Lesson Basket. See also our GATE-XL weightage analysis.
Q104Food Chemistry & NutritionXL-U Q.1 · MCQ · 1 mark, −1/3 for a wrong answer

Which of the following contains the phytonutrient allicin?

  1. AGrape
  2. BCauliflower
  3. CGarlic
  4. DChilli
Show answer
Answer: (C) Garlic
Q105Food MicrobiologyXL-U Q.2 · MCQ · 1 mark, −1/3 for a wrong answer

Which mold is responsible for the characteristic blue marbling in blue-veined cheese?

  1. ARhizopus oryzae
  2. BPenicillium roqueforti
  3. CAspergillus niger
  4. DPenicillium camemberti
Show answer
Answer: (B) Penicillium roqueforti
Q106Food MicrobiologyXL-U Q.3 · MCQ · 1 mark, −1/3 for a wrong answer

Which genus of bacteria does NOT have cell wall?

  1. ALactobacillus
  2. BStaphylococcus
  3. CMycoplasma
  4. DEscherichia
Show answer
Answer: (C) Mycoplasma
Q107Food Chemistry & NutritionXL-U Q.4 · MCQ · 1 mark, −1/3 for a wrong answer

Which of the following pigment does NOT have pro-vitamin A activity?

  1. Aβ-Carotene
  2. Bβ-Cryptoxanthin
  3. CLycopene
  4. Dα-Carotene
Show answer
Answer: (C) Lycopene
Q108Food Products TechnologyXL-U Q.5 · MCQ · 1 mark, −1/3 for a wrong answer

Identify the analysis that must be performed FIRST to judge ‘cleanliness’ of spice/herb powders.

  1. AAcid-insoluble ash content
  2. BPesticide residue levels
  3. CVolatile oil content
  4. DMycotoxin levels
Show answer
Answer: (A) Acid-insoluble ash content
Q109Food Products TechnologyXL-U Q.6 · MCQ · 1 mark, −1/3 for a wrong answer

If there is a delay in oil extraction after bran is separated from the brown rice, the quality of rice bran oil deteriorates. Identify the suitable CAUSE and EFFECT for the deterioration in oil quality.

  1. ALipase activity; increase in FFA
  2. BOil hydrolysis; decrease in FFA
  3. CLipase activity; decrease in FFA
  4. DBran stabilization; decrease in lipase activity
Show answer
Answer: (A) Lipase activity; increase in FFA
Q110Food Chemistry & NutritionXL-U Q.7 · MSQ (one or more correct) · 1 mark, no negative marking

Among the following, which is/are the process(es) that lead to generation of new fats from existing ones?

  1. ATransesterification
  2. BDegumming
  3. CHydrogenation
  4. DWinterization
Show answer
Answer (select all of these): (A) Transesterification and (C) Hydrogenation
Q111Food EngineeringXL-U Q.8 · Numerical answer · 1 mark, no negative marking

The true density and bulk density of wheat grains are 1280 kg/m3 and 740 kg/m3, respectively. The porosity of the grains is ____. (rounded off to 2 decimal places)

Type a number as your answer.

Show answer
Answer: any value from 0.40 to 0.44 (numerical answer, as in the official key).
Q112Food Products TechnologyXL-U Q.9 · MCQ · 2 marks, −2/3 for a wrong answer

Identify the gas composition (in percent) suitable for packaging cured meat under MAP conditions.

  1. AO2 = 0; CO2 = 50; N2 = 50
  2. BO2 = 50; CO2 = 0; N2 = 50
  3. CO2 = 0; CO2 = 0; N2 = 100
  4. DO2 = 50; CO2 = 50; N2 = 0
Show answer
Answer: (A) O2 = 0; CO2 = 50; N2 = 50
Q113Food Chemistry & NutritionXL-U Q.10 · MCQ · 2 marks, −2/3 for a wrong answer

Which of the following sequence of events occurs during formation of egg-white gel?

Assume: PN: Native protein; PD: Denatured protein; PA: Aggregated protein; PG: Protein gel
→: forward reaction; ↔: reversible reaction; Δ: heating; ∇: cooling (the symbol written over an arrow is shown here after it)

  1. APN ↔Δ PD ↔∇ PA ↔∇ PG
  2. BPN ↔Δ PD →Δ PA →Δ PG
  3. CPN ↔Δ PD →∇ PG
  4. DPN ↔Δ PA →Δ PG
Show answer
Answer: (B) PN ↔Δ PD →Δ PA →Δ PG
Q114Food EngineeringXL-U Q.11 · MCQ · 2 marks, −2/3 for a wrong answer

In canning and retorting of foods, which of the following is the correct expression of Ball process time (B)? Assume: tp = processor’s process time; tc = come-up time

  1. AB = tp + 0.42 tc
  2. BB = tp + 0.30 tc
  3. CB = tp + 0.50 tc
  4. DB = tp + 0.25 tc
Show answer
Answer: (A) B = tp + 0.42 tc
Q115Food Products TechnologyXL-U Q.12 · MCQ · 2 marks, −2/3 for a wrong answer

Which of the following is the most suitable flexible packaging laminate for dry fruits?

  1. APET/LDPE
  2. BPS/LDPE
  3. CBOPP/LDPE
  4. DNylon/LDPE
Show answer
Answer: (C) BOPP/LDPE
Q116Food Products TechnologyXL-U Q.13 · MCQ · 2 marks, −2/3 for a wrong answer

Identify the CORRECT sequence of operations for dressing of poultry.

  1. ASlaughtering and bleeding → scalding → defeathering → eviscerating → chilling
  2. BSlaughtering and bleeding → defeathering → scalding → eviscerating → chilling
  3. CSlaughtering and bleeding → eviscerating → defeathering → scalding → chilling
  4. DSlaughtering and bleeding → defeathering → eviscerating → scalding → chilling
Show answer
Answer: (A) Slaughtering and bleeding → scalding → defeathering → eviscerating → chilling
Q117Food MicrobiologyXL-U Q.14 · MSQ (one or more correct) · 2 marks, no negative marking

Which of the following statement(s) is/are TRUE for a package of gamma- irradiated (7.5 kGy) whole chicken?

  1. ANutritional quality of the product deteriorates after irradiation.
  2. BSpores of C. botulinum can survive in the irradiated product.
  3. C‘Radura’ symbol does not ensure safety of the irradiated product for consumption.
  4. DEnergy needed for the irradiation process is much higher than that required for freezing of the product.
Show answer
Answer (select all of these): (B) Spores of C. botulinum can survive in the irradiated product. and (C) ‘Radura’ symbol does not ensure safety of the irradiated product for consumption.
Q118Food Products TechnologyXL-U Q.15 · MSQ (one or more correct) · 2 marks, no negative marking

Match the following food products in Column I with their corresponding processes in Column II.

Column IColumn II
P Idli1 Baking
Q Parboiled rice2 Fermentation
R Soda beverage3 Gelatinization
S Cookies4 Carbonation
  1. AP-2;Q-3;R-4;S-1
  2. BP-3;Q-2;R-4;S-1
  3. CP-2;Q-4;R-1;S-3
  4. DP-2;Q-3;R-1;S-4
Show answer
Answer (select all of these): (A) P-2;Q-3;R-4;S-1
Q119Food Chemistry & NutritionXL-U Q.16 · MSQ (one or more correct) · 2 marks, no negative marking

Which of the following is/are inhibitor(s) of enzymatic browning in peeled potatoes?

  1. ACitric acid
  2. BEDTA
  3. CMannitol
  4. DAscorbic acid
Show answer
Answer (select all of these): (A) Citric acid and (B) EDTA and (D) Ascorbic acid
Q120Food Chemistry & NutritionXL-U Q.17 · MSQ (one or more correct) · 2 marks, no negative marking

Match the following enzymes in Column I with their applications in Column II.

Column IColumn II
P β-Glucanase1 Fruit juice clarification
Q α- and β-Amylases2 Bread making
R Pectinase3 Meat tenderization
S Papain4 Brewing
  1. AP-3;Q-1;R-2;S-4
  2. BP-4;Q-2;R-1;S-3
  3. CP-2;Q-4;R-1;S-3
  4. DP-1;Q-2;R-3;S-4
Show answer
Answer (select all of these): (B) P-4;Q-2;R-1;S-3 and (C) P-2;Q-4;R-1;S-3
Q121Food EngineeringXL-U Q.18 · Numerical answer · 2 marks, no negative marking

The F121 value of a known microorganism with Z value of 11 °C is 2.4 min for 99.9999% inactivation. For a 12D inactivation of the said microorganism at 143 °C, the F value (in min) is _____. (rounded off to 3 decimal places)

Type a number as your answer.

Show answer
Answer: any value from 0.046 to 0.050 (numerical answer, as in the official key).
Q122Food EngineeringXL-U Q.19 · Numerical answer · 2 marks, no negative marking

In a typical grinding operation, 80% of the feed material passes through a sieve opening of 4.75 mm; whereas, 80% of the ground product passes through 0.5 mm opening. If the power required to grind 2 tonnes/h of the feed material is 3.8 kW, the work index of the material is _______. (rounded off to 2 decimal places)

Type a number as your answer.

Show answer
Answer: any value from 6.25 to 6.32 (numerical answer, as in the official key).

Changes in the final answer key

No question was dropped or given marks to all in the final key, so each question below has the answer shown.

How to revise from this paper

  1. Pick your two optional sections firstAttempt GA, XL-P and the two sections you plan to choose, 65 questions in one 3-hour sitting.
  2. Score it the GATE wayAdd 1 or 2 marks per correct answer and subtract 1/3 or 2/3 only for wrong MCQs. MSQ must be fully correct to score.
  3. Sort your mistakes by topicUse the topic tag on each question. Two or three misses in the same topic show where to revise first.
  4. Repeat with another yearTake a different year a week later and compare your topic-wise mistakes.

Keep going

Ready for full-length mocks? Try the GATE-XL Life Sciences Full Test Series
The GATE-XL Life Sciences Full Test Series gives you full-length mocks on the GATE pattern, with MCQ, MSQ and numerical questions and GATE marking.
Source: GATE 2025 Life Sciences (XL) question paper and final answer key, published by the organising institute (IIT Roorkee). Question text is reproduced for practice; any transcription error is ours, and the official documents are the authority.
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